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y ′ × ( x 2 y 3 + x y ) = 1 y' \times \big(x^2 y^3 + xy \big) = 1 y′×(x2y3+xy)=1
The general solution of the differential equation above is ____________________ . \text{\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_}. ____________________.
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