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1 ( x − 1 ) ( x − 2 ) + 1 ( x − 2 ) ( x − 3 ) + 1 ( x − 3 ) ( x − 4 ) = 1 6 \frac{1}{(x-1)(x-2)} + \frac{1}{(x-2)(x-3)} + \frac{1}{(x-3)(x-4)} = \frac{1}{6} (x−1)(x−2)1+(x−2)(x−3)1+(x−3)(x−4)1=61
What is the sum of all real values of x x xthat satisfy the above equation?
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byavn bha