保理二次方程式论据/h1>
已经有账户了?据一种href="//www.parkandroid.com/account/login/?next=/wiki/factoring-quadratics/" class="ax-click" data-ax-id="clicked_signup_modal_login" data-ax-type="link">这里登录。据/a>
测验据/h4>
有关……据/h4>
- 代数据/span>>据/span>
二次因式分解法是一种简化二次表达式和求解方程的方法。常见的情况包括三项式分解和平方和分解。据/p>
一个二次表达式可以写成和,据span class="katex"> X据/span>2据/span>+据/span>7.据/span>X据/span>+据/span>1据/span>2据/span>那据/span>或者作为产品据span class="katex"> (据/span>X据/span>+据/span>3.据/span>)据/span>(据/span>X据/span>+据/span>4.据/span>)据/span>那据/span>就像14可以写成乘积一样,据span class="katex"> 7.据/span>×据/span>2据/span>那据/span>或总和,据span class="katex"> 6.据/span>+据/span>8.据/span>.据/span>三项式的因式分解是把和写成乘积的过程。据/p>
内容据/h4>
领导系数= 1据/h2>
二次表达式可以写成标准形式据span class="katex"> 一种据/span>X据/span>2据/span>+据/span>B.据/span>X据/span>+据/span>C据/span>.据/span>
让我们从分解三项式开始据span class="katex"> 一种据/span>=据/span>1据/span>那据/span>如据span class="katex"> X据/span>2据/span>+据/span>8.据/span>X据/span>+据/span>1据/span>5.据/span>.据/span>
首先,我们需要找到产品据span class="katex"> 一种据/span>C据/span>:据/span> 一种据/span>C据/span>=据/span>(据/span>1据/span>)据/span>(据/span>1据/span>5.据/span>)据/span>=据/span>1据/span>5.据/span>.据/span>
接下来,我们需要找到一个因素对据span class="katex">
一种据/span>C据/span>该款项据span class="katex">
B.据/span>.据/span>因此,我们需要一个因子对15款项8.因子对3个5总和为8。据/p>
接下来,我们需要重写据span class="katex">
B.据/span>-term”使用我们的新的和我们的二次的:据span class="katex-display">
X据/span>2据/span>+据/span>3.据/span>X据/span>+据/span>5.据/span>X据/span>+据/span>1据/span>5.据/span>.据/span> 最后,我们可以通过分组分解,将表达式的前两项和后两项进行分解:据span class="katex-display">
(据/span>X据/span>2据/span>+据/span>3.据/span>X据/span>)据/span>+据/span>(据/span>5.据/span>X据/span>+据/span>1据/span>5.据/span>)据/span>=据/span>X据/span>(据/span>X据/span>+据/span>3.据/span>)据/span>+据/span>5.据/span>(据/span>X据/span>+据/span>3.据/span>)据/span>=据/span>(据/span>X据/span>+据/span>5.据/span>)据/span>(据/span>X据/span>+据/span>3.据/span>)据/span>.据/span> 的因子形式据span class="katex">
X据/span>2据/span>+据/span>8.据/span>X据/span>+据/span>1据/span>5.据/span>是据span class="katex">
(据/span>X据/span>+据/span>3.据/span>)据/span>(据/span>X据/span>+据/span>5.据/span>)据/span>.据/span> 的产物据span class="katex">
一种据/span>和据span class="katex">
C据/span>是据span class="katex">
(据/span>1据/span>)据/span>(据/span>-据/span>1据/span>2据/span>)据/span>=据/span>-据/span>1据/span>2据/span>.据/span> 因素对据span class="katex">
-据/span>1据/span>2据/span>该款项据span class="katex">
-据/span>4.据/span>是据span class="katex">
-据/span>6.据/span>和据span class="katex">
2据/span>.据/span> 把表达式改写一下据span class="katex">
X据/span>2据/span>-据/span>4.据/span>X据/span>-据/span>1据/span>2据/span>=据/span>X据/span>2据/span>-据/span>6.据/span>X据/span>+据/span>2据/span>X据/span>-据/span>1据/span>2据/span>.据/span> 分组和简化,我们有据span class="katex">
X据/span>2据/span>-据/span>6.据/span>X据/span>+据/span>2据/span>X据/span>-据/span>1据/span>2据/span>=据/span>(据/span>X据/span>2据/span>-据/span>6.据/span>X据/span>)据/span>+据/span>(据/span>2据/span>X据/span>-据/span>1据/span>2据/span>)据/span>=据/span>X据/span>(据/span>X据/span>-据/span>6.据/span>)据/span>+据/span>2据/span>(据/span>X据/span>-据/span>6.据/span>)据/span>=据/span>(据/span>X据/span>+据/span>2据/span>)据/span>(据/span>X据/span>-据/span>6.据/span>)据/span>.据/span> 的因子形式据span class="katex">
X据/span>2据/span>-据/span>4.据/span>X据/span>-据/span>1据/span>2据/span>是据span class="katex">
(据/span>X据/span>+据/span>2据/span>)据/span>(据/span>X据/span>-据/span>6.据/span>)据/span>.据/span> 的产物据span class="katex">
一种据/span>和据span class="katex">
C据/span>是据span class="katex">
(据/span>1据/span>)据/span>(据/span>6.据/span>)据/span>=据/span>6.据/span>.据/span> 因素对据span class="katex">
6.据/span>该款项据span class="katex">
-据/span>7.据/span>是据span class="katex">
-据/span>1据/span>和据span class="katex">
-据/span>6.据/span>.据/span> 把表达式改写一下据span class="katex">
X据/span>2据/span>-据/span>7.据/span>X据/span>+据/span>6.据/span>=据/span>X据/span>2据/span>-据/span>1据/span>X据/span>-据/span>6.据/span>X据/span>+据/span>6.据/span>.据/span> 分组和简化,我们有据span class="katex">
X据/span>2据/span>-据/span>1据/span>X据/span>-据/span>6.据/span>X据/span>+据/span>6.据/span>=据/span>(据/span>X据/span>2据/span>-据/span>1据/span>X据/span>)据/span>+据/span>(据/span>-据/span>6.据/span>X据/span>+据/span>6.据/span>)据/span>=据/span>X据/span>(据/span>X据/span>-据/span>1据/span>)据/span>-据/span>6.据/span>(据/span>X据/span>-据/span>1据/span>)据/span>=据/span>(据/span>X据/span>-据/span>6.据/span>)据/span>(据/span>X据/span>-据/span>1据/span>)据/span>.据/span> 的因子形式据span class="katex">
X据/span>2据/span>-据/span>7.据/span>X据/span>+据/span>6.据/span>是据span class="katex">
(据/span>X据/span>-据/span>6.据/span>)据/span>(据/span>X据/span>-据/span>1据/span>)据/span>.据/span>
X据/span>2据/span>+据/span>5.据/span>X据/span>-据/span>1据/span>4.据/span>=据/span>(据/span>X据/span>+据/span>一种据/span>)据/span>(据/span>X据/span>-据/span>2据/span>)据/span> 观察方程的左边可以被分解为据span class="katex-display">
X据/span>2据/span>+据/span>5.据/span>X据/span>-据/span>1据/span>4.据/span>=据/span>X据/span>2据/span>+据/span>7.据/span>X据/span>-据/span>2据/span>X据/span>+据/span>7.据/span>⋅据/span>(据/span>-据/span>2据/span>)据/span>=据/span>X据/span>(据/span>X据/span>+据/span>7.据/span>)据/span>-据/span>2据/span>(据/span>X据/span>+据/span>7.据/span>)据/span>=据/span>(据/span>X据/span>+据/span>7.据/span>)据/span>(据/span>X据/span>-据/span>2据/span>)据/span>.据/span>与右侧等同这给据span class="katex">
一种据/span>=据/span>7.据/span>.据/p>
P.据/span>2据/span>+据/span>5.据/span>P.据/span>+据/span>6.据/span> 下面哪个解是这个三项式的正确因式。据/p>
因素据span class="katex">
X据/span>2据/span>-据/span>4.据/span>X据/span>-据/span>1据/span>2据/span>.据/span>
因素据span class="katex">
X据/span>2据/span>-据/span>7.据/span>X据/span>+据/span>6.据/span>.据/span>
如果下面的陈述是正确的,值是多少据span class="katex">
一种据/span>还是据/span>
首项系数据span class="katex"> 据/span>=据/span>1据/h2>
请记住,二次表达式可以在标准的形式被写入据span class="katex"> 一种据/span>X据/span>2据/span>+据/span>B.据/span>X据/span>+据/span>C据/span>.据/span>让我们因素的一些表述中,据span class="katex"> 一种据/span>据/span>=据/span>1据/span>.据/span>
我们将首先据span class="katex">
2据/span>X据/span>2据/span>+据/span>7.据/span>X据/span>+据/span>3.据/span>那据/span>然后按照上述相同的步骤..据/p>
首先,我们需要找到产品据span class="katex">
一种据/span>C据/span>:据/span>
一种据/span>⋅据/span>C据/span>=据/span>2据/span>⋅据/span>3.据/span>=据/span>6.据/span>.据/span> 接下来,我们需要找到一个因素对据span class="katex">
一种据/span>C据/span>该款项据span class="katex">
B.据/span>.据/span>因此,我们需要一个因素对6中的款项至7因子对6个1总和为7。据/p>
接下来,我们需要重写据span class="katex">
B.据/span>-term”使用我们的新的和我们的二次的:据span class="katex-display">
2据/span>X据/span>2据/span>+据/span>6.据/span>X据/span>+据/span>1据/span>X据/span>+据/span>3.据/span>.据/span> 最后,我们可以通过分组分解,将表达式的前两项和后两项进行分解:据span class="katex-display">
(据/span>2据/span>X据/span>2据/span>+据/span>6.据/span>X据/span>)据/span>+据/span>(据/span>1据/span>X据/span>+据/span>3.据/span>)据/span>=据/span>2据/span>X据/span>(据/span>X据/span>+据/span>3.据/span>)据/span>+据/span>1据/span>(据/span>X据/span>+据/span>3.据/span>)据/span>=据/span>(据/span>2据/span>X据/span>+据/span>1据/span>)据/span>(据/span>X据/span>+据/span>3.据/span>)据/span>.据/span> 的因子形式据span class="katex">
2据/span>X据/span>2据/span>+据/span>7.据/span>X据/span>+据/span>3.据/span>是据span class="katex">
(据/span>2据/span>X据/span>+据/span>1据/span>)据/span>(据/span>X据/span>+据/span>3.据/span>)据/span>.据/span> 的产物据span class="katex">
一种据/span>和据span class="katex">
C据/span>是据span class="katex">
(据/span>3.据/span>)据/span>(据/span>-据/span>8.据/span>)据/span>=据/span>-据/span>2据/span>4.据/span>.据/span> 因素对据span class="katex">
-据/span>2据/span>4.据/span>该款项据span class="katex">
1据/span>0.据/span>是据span class="katex">
1据/span>2据/span>和据span class="katex">
-据/span>2据/span>.据/span> 把表达式改写一下据span class="katex">
3.据/span>X据/span>2据/span>+据/span>1据/span>0.据/span>X据/span>-据/span>8.据/span>=据/span>3.据/span>X据/span>2据/span>+据/span>1据/span>2据/span>X据/span>-据/span>2据/span>X据/span>-据/span>8.据/span>.据/span> 分组和简化,我们有据span class="katex">
3.据/span>X据/span>2据/span>+据/span>1据/span>2据/span>X据/span>-据/span>2据/span>X据/span>-据/span>8.据/span>=据/span>(据/span>3.据/span>X据/span>2据/span>+据/span>1据/span>2据/span>X据/span>)据/span>+据/span>(据/span>-据/span>2据/span>X据/span>-据/span>8.据/span>)据/span>=据/span>3.据/span>X据/span>(据/span>X据/span>+据/span>4.据/span>)据/span>-据/span>2据/span>(据/span>X据/span>+据/span>4.据/span>)据/span>=据/span>(据/span>3.据/span>X据/span>-据/span>2据/span>)据/span>(据/span>X据/span>+据/span>4.据/span>)据/span>.据/span> 的因子形式据span class="katex">
3.据/span>X据/span>2据/span>+据/span>1据/span>0.据/span>X据/span>-据/span>8.据/span>是据span class="katex">
(据/span>3.据/span>X据/span>-据/span>2据/span>)据/span>(据/span>X据/span>+据/span>4.据/span>)据/span>.据/span>
如果据span class="katex">
(据/span>X据/span>+据/span>4.据/span>)据/span>(据/span>3.据/span>X据/span>-据/span>1据/span>)据/span>=据/span>一种据/span>X据/span>2据/span>+据/span>B.据/span>X据/span>+据/span>C据/span>那据/span>价值是什么据span class="katex">
一种据/span>+据/span>B.据/span>+据/span>C据/span>还是据/span>
因素据span class="katex">
3.据/span>X据/span>2据/span>+据/span>1据/span>0.据/span>X据/span>-据/span>8.据/span>.据/span>
公约数据/h2>
有时,我们可以在完全分解三项式之前,先分解出公因式来简化二次表达式。据/p>
例如,我们考虑因式分解据span class="katex"> 6.据/span>X据/span>2据/span>-据/span>1据/span>5.据/span>X据/span>-据/span>3.据/span>6.据/span>.据/span>
三项式中的每一项都能被3整除所以我们提出一个3:据span class="katex"> 6.据/span>X据/span>2据/span>-据/span>1据/span>5.据/span>X据/span>-据/span>3.据/span>6.据/span>=据/span>3.据/span>(据/span>2据/span>X据/span>2据/span>-据/span>5.据/span>X据/span>-据/span>1据/span>2据/span>)据/span>.据/span>
现在,我们可以因素据span class="katex">
2据/span>X据/span>2据/span>-据/span>5.据/span>X据/span>-据/span>1据/span>2据/span>下面,我们上面使用的相同的过程。据/p>
的价值据span class="katex">
一种据/span>C据/span>是据span class="katex">
(据/span>2据/span>)据/span>(据/span>-据/span>1据/span>2据/span>)据/span>=据/span>-据/span>2据/span>4.据/span>.据/span>该因素对据span class="katex">
-据/span>2据/span>4.据/span>该款项据span class="katex">
-据/span>5.据/span>是8,据span class="katex">
-据/span>3.据/span>.据/span> 因此,据span class="katex-display">
3.据/span>(据/span>2据/span>X据/span>2据/span>-据/span>5.据/span>X据/span>-据/span>1据/span>2据/span>)据/span>=据/span>3.据/span>(据/span>2据/span>X据/span>2据/span>+据/span>8.据/span>X据/span>-据/span>3.据/span>X据/span>-据/span>1据/span>2据/span>)据/span>=据/span>3.据/span>[据/span>(据/span>2据/span>X据/span>2据/span>+据/span>8.据/span>X据/span>)据/span>+据/span>(据/span>-据/span>3.据/span>X据/span>-据/span>1据/span>2据/span>)据/span>]据/span>=据/span>3.据/span>[据/span>2据/span>X据/span>(据/span>X据/span>+据/span>4.据/span>)据/span>-据/span>3.据/span>(据/span>X据/span>+据/span>4.据/span>)据/span>]据/span>=据/span>3.据/span>(据/span>2据/span>X据/span>-据/span>3.据/span>)据/span>(据/span>X据/span>+据/span>4.据/span>)据/span>.据/span> 首先,让我们通过分解出一个10:据span class="katex">
2据/span>0.据/span>X据/span>2据/span>-据/span>3.据/span>0.据/span>X据/span>+据/span>1据/span>0.据/span>=据/span>1据/span>0.据/span>(据/span>2据/span>X据/span>2据/span>-据/span>3.据/span>X据/span>+据/span>1据/span>)据/span>.据/span> 的产物据span class="katex">
一种据/span>和据span class="katex">
C据/span>是据span class="katex">
(据/span>2据/span>)据/span>(据/span>1据/span>)据/span>=据/span>2据/span>.据/span> 因素对据span class="katex">
2据/span>该款项据span class="katex">
-据/span>3.据/span>是据span class="katex">
-据/span>1据/span>和据span class="katex">
-据/span>2据/span>.据/span> 因此,据span class="katex-display">
1据/span>0.据/span>(据/span>2据/span>X据/span>2据/span>-据/span>3.据/span>X据/span>+据/span>1据/span>)据/span>=据/span>1据/span>0.据/span>[据/span>2据/span>X据/span>2据/span>-据/span>1据/span>X据/span>-据/span>2据/span>X据/span>+据/span>1据/span>]据/span>=据/span>1据/span>0.据/span>[据/span>(据/span>2据/span>X据/span>2据/span>-据/span>1据/span>X据/span>)据/span>+据/span>(据/span>-据/span>2据/span>X据/span>+据/span>1据/span>)据/span>]据/span>=据/span>1据/span>0.据/span>[据/span>X据/span>(据/span>2据/span>X据/span>-据/span>1据/span>)据/span>-据/span>1据/span>(据/span>2据/span>X据/span>-据/span>1据/span>)据/span>]据/span>=据/span>1据/span>0.据/span>(据/span>X据/span>-据/span>1据/span>)据/span>(据/span>2据/span>X据/span>-据/span>1据/span>)据/span>.据/span>
因素据span class="katex">
2据/span>0.据/span>X据/span>2据/span>-据/span>3.据/span>0.据/span>X据/span>+据/span>1据/span>0.据/span>.据/span>
二次因式分解-基础据/h2>
给定一个二次方程据span class="katex">
一种据/span>X据/span>2据/span>+据/span>B.据/span>X据/span>+据/span>C据/span>=据/span>0.据/span>如何分解?据/p>
首先,我们需要知道二次方程的因式形式是据span class="katex">
一种据/span>(据/span>X据/span>-据/span>R.据/span>1据/span>)据/span>(据/span>X据/span>-据/span>R.据/span>2据/span>)据/span>, 在哪里据span class="katex">
R.据/span>1据/span>和据span class="katex">
R.据/span>2据/span>是方程的根和据span class="katex">
一种据/span>是第一项的系数。据/p>
通过扩展,我们得到据span class="katex">
一种据/span>(据/span>X据/span>2据/span>-据/span>(据/span>R.据/span>1据/span>+据/span>R.据/span>2据/span>)据/span>X据/span>+据/span>R.据/span>1据/span>R.据/span>2据/span>)据/span>.据/p>
现在,我们可以尝试系数方程,但首先我们需要走出因素据span class="katex">
一种据/span>,这是第一项的系数。然后,我们可以尝试一些价值发现方程的根,因为我们知道据span class="katex">
一种据/span>-据/span>B.据/span>=据/span>R.据/span>1据/span>+据/span>R.据/span>2据/span>和据span class="katex">
一种据/span>C据/span>=据/span>R.据/span>1据/span>R.据/span>2据/span>.据/p>
我们并不需要分解出据span class="katex">
一种据/span>自据span class="katex">
一种据/span>=据/span>1据/span>.据/p>
现在我们知道了据span class="katex">
R.据/span>1据/span>+据/span>R.据/span>2据/span>=据/span>-据/span>B.据/span>=据/span>7.据/span>和据span class="katex">
R.据/span>1据/span>R.据/span>2据/span>=据/span>C据/span>=据/span>6.据/span>我们知道,值据span class="katex">
1据/span>和据span class="katex">
6.据/span>满足条件据span class="katex">
R.据/span>1据/span>和据span class="katex">
R.据/span>2据/span>.据/p>
因此,据span class="katex-display">
X据/span>2据/span>-据/span>7.据/span>X据/span>+据/span>6.据/span>=据/span>(据/span>X据/span>-据/span>6.据/span>)据/span>(据/span>X据/span>-据/span>1据/span>)据/span>.据/span>□据/span>
因式分解据span class="katex">
X据/span>2据/span>-据/span>7.据/span>X据/span>+据/span>6.据/span>.据/h3>
二次方程式保理 - 中级据/h2>
给定一个二次方程据span class="katex">
一种据/span>X据/span>2据/span>+据/span>B.据/span>X据/span>+据/span>C据/span>=据/span>0.据/span>,我们可以很容易地使用所述方法分解它据一种target="_blank" rel="nofollow" href="//www.parkandroid.com/wiki/quadratics-factoring-easy/">在这里据/a>.然而,当处理解不是实数的一般二次方程时,这可能不是最好的方法。对于这些情况,二次公式可能更适用。据/p>
考虑二次方程据span class="katex">
一种据/span>X据/span>2据/span>+据/span>B.据/span>X据/span>+据/span>C据/span>=据/span>0.据/span>.如果我们把整个表达据span class="katex">
一种据/span>,我们得到据span class="katex-display">
X据/span>2据/span>+据/span>一种据/span>B.据/span>X据/span>+据/span>一种据/span>C据/span>=据/span>0.据/span>.据/span>重新排列使据span class="katex-display">
X据/span>2据/span>+据/span>一种据/span>B.据/span>X据/span>=据/span>-据/span>一种据/span>C据/span>.据/span>现在,让我们添加据span class="katex">
4.据/span>一种据/span>2据/span>B.据/span>2据/span>双方:据span class="katex-display">
X据/span>2据/span>+据/span>4.据/span>一种据/span>2据/span>B.据/span>2据/span>+据/span>一种据/span>B.据/span>X据/span>(据/span>X据/span>+据/span>2据/span>一种据/span>B.据/span>)据/span>2据/span>=据/span>4.据/span>一种据/span>2据/span>B.据/span>2据/span>-据/span>一种据/span>C据/span>=据/span>4.据/span>一种据/span>2据/span>B.据/span>2据/span>-据/span>4.据/span>一种据/span>C据/span>.据/span>以双方的平方根,我们有据span class="katex-display">
X据/span>+据/span>2据/span>一种据/span>B.据/span>=据/span>±据/span>4.据/span>一种据/span>2据/span>B.据/span>2据/span>-据/span>4.据/span>一种据/span>C据/span>
.据/span>重新排列最后一次,我们得到据span class="katex-display">
X据/span>=据/span>2据/span>一种据/span>-据/span>B.据/span>±据/span>B.据/span>2据/span>-据/span>4.据/span>一种据/span>C据/span>
.据/span> 请注意,现在我们能够找到一个二次的根源,即使他们是不是真实的。这让我们很容易因素吧。因此,对于任何二次据span class="katex">
一种据/span>X据/span>2据/span>+据/span>B.据/span>X据/span>+据/span>C据/span>=据/span>0.据/span>,我们可以把它分解成据span class="katex">
K.据/span>(据/span>X据/span>+据/span>α据/span>)据/span>(据/span>X据/span>+据/span>β据/span>)据/span>=据/span>0.据/span>, 在哪里据span class="katex">
α据/span>=据/span>2据/span>一种据/span>-据/span>B.据/span>+据/span>B.据/span>2据/span>-据/span>4.据/span>一种据/span>C据/span>
那据/span>
β据/span>=据/span>2据/span>一种据/span>-据/span>B.据/span>-据/span>B.据/span>2据/span>-据/span>4.据/span>一种据/span>C据/span>
那据/span>和据span class="katex">
K.据/span>是一个常数。据/p>
使用我们的公式,我们得到据span class="katex-display">
ϕ据/span>=据/span>2据/span>一种据/span>-据/span>B.据/span>+据/span>B.据/span>2据/span>-据/span>4.据/span>一种据/span>C据/span>
=据/span>2据/span>-据/span>1据/span>+据/span>5.据/span>
那据/span>Φ据/span>=据/span>2据/span>一种据/span>-据/span>B.据/span>-据/span>B.据/span>2据/span>-据/span>4.据/span>一种据/span>C据/span>
=据/span>2据/span>-据/span>1据/span>-据/span>5.据/span>
.据/span>我们的二次因此,据span class="katex-display">
K.据/span>(据/span>X据/span>-据/span>ϕ据/span>)据/span>(据/span>X据/span>-据/span>Φ据/span>)据/span>=据/span>0.据/span>为一个常数据span class="katex">
K.据/span>.但是,由于我们的第一个任期内的领先系数为1,我们知道因式分解必须据span class="katex-display">
(据/span>X据/span>-据/span>ϕ据/span>)据/span>(据/span>X据/span>-据/span>Φ据/span>)据/span>=据/span>(据/span>X据/span>-据/span>2据/span>-据/span>1据/span>+据/span>5.据/span>
)据/span>(据/span>X据/span>-据/span>2据/span>-据/span>1据/span>-据/span>5.据/span>
)据/span>.据/span>□据/span> 因式分解的这种方法,当我们面对的不是与真正的解决方案/二次方程式的系数也适用。据/p>
首先,我们观察到,由于其判别为负这并没有真正的解决方案:据span class="katex-display">
D.据/span>=据/span>B.据/span>2据/span>-据/span>4.据/span>一种据/span>C据/span>=据/span>2据/span>2据/span>-据/span>4.据/span>×据/span>2据/span>×据/span>2据/span>=据/span>-据/span>1据/span>2据/span>据据/span>0.据/span>.据/span>我们可以继续寻找它的根据span class="katex-display">
X据/span>=据/span>2据/span>一种据/span>-据/span>B.据/span>+据/span>B.据/span>2据/span>-据/span>4.据/span>一种据/span>C据/span>
=据/span>2据/span>一种据/span>-据/span>B.据/span>+据/span>D.据/span>
.据/span>使用我们的公式据span class="katex-display">
α据/span>=据/span>2据/span>.据/span>2据/span>-据/span>2据/span>+据/span>-据/span>1据/span>2据/span>
=据/span>4.据/span>-据/span>2据/span>+据/span>4.据/span>×据/span>-据/span>1据/span>×据/span>3.据/span>
=据/span>4.据/span>-据/span>2据/span>+据/span>2据/span>一世据/span>3.据/span>
=据/span>2据/span>-据/span>1据/span>+据/span>2据/span>一世据/span>3.据/span>
.据/span>同样,我们得到据span class="katex-display">
β据/span>=据/span>2据/span>.据/span>2据/span>-据/span>2据/span>-据/span>-据/span>1据/span>2据/span>
=据/span>4.据/span>-据/span>2据/span>-据/span>4.据/span>×据/span>-据/span>1据/span>×据/span>3.据/span>
=据/span>4.据/span>-据/span>2据/span>-据/span>2据/span>一世据/span>3.据/span>
=据/span>2据/span>-据/span>1据/span>-据/span>2据/span>一世据/span>3.据/span>
.据/span> 现在,我们可以写我们的方程据span class="katex-display">
K.据/span>(据/span>X据/span>-据/span>2据/span>-据/span>1据/span>-据/span>2据/span>一世据/span>3.据/span>
)据/span>(据/span>X据/span>-据/span>2据/span>-据/span>1据/span>+据/span>2据/span>一世据/span>3.据/span>
)据/span>=据/span>0.据/span>.据/span>注意据span class="katex">
K.据/span>必须是据span class="katex">
2据/span>为了使系数据span class="katex">
X据/span>2据/span>
2据/span>.因此,我们终于得到据span class="katex-display">
2据/span>(据/span>X据/span>+据/span>2据/span>1据/span>-据/span>2据/span>3.据/span>
一世据/span>)据/span>(据/span>X据/span>+据/span>2据/span>1据/span>+据/span>2据/span>3.据/span>
一世据/span>)据/span>=据/span>0.据/span>.据/span>□据/span> 这让我们因式分解与非理性,甚至虚系数二次方程式。据/p>
同样,我们的判别是据span class="katex-display">
D.据/span>=据/span>B.据/span>2据/span>-据/span>4.据/span>×据/span>一种据/span>×据/span>C据/span>=据/span>5.据/span>0.据/span>-据/span>4.据/span>×据/span>1据/span>2据/span>=据/span>2据/span>>据/span>0.据/span>.据/span>使用我们的公式,我们得到据span class="katex-display">
α据/span>β据/span>=据/span>4.据/span>6.据/span>
-据/span>5.据/span>2据/span>
+据/span>2据/span>
=据/span>4.据/span>6.据/span>
-据/span>4.据/span>2据/span>
=据/span>-据/span>3.据/span>3.据/span>
=据/span>4.据/span>6.据/span>
-据/span>5.据/span>2据/span>
-据/span>2据/span>
=据/span>4.据/span>6.据/span>
-据/span>6.据/span>2据/span>
=据/span>-据/span>2据/span>3.据/span>
.据/span> 因此,我们的分解成为据/p>
K.据/span>(据/span>X据/span>+据/span>3.据/span>3.据/span>
)据/span>(据/span>X据/span>+据/span>2据/span>3.据/span>
)据/span>=据/span>0.据/span>.据/span> 此外,通过这个我们最初的多项式的比较,我们可以看到,据span class="katex">
K.据/span>=据/span>2据/span>4.据/span>
=据/span>2据/span>6.据/span>
.因此,我们最终的分解形式是据span class="katex-display">
2据/span>4.据/span>
(据/span>X据/span>+据/span>3.据/span>3.据/span>
)据/span>(据/span>X据/span>+据/span>2据/span>3.据/span>
)据/span>=据/span>0.据/span>.据/span>□据/span>
因式分解据span class="katex">
X据/span>2据/span>+据/span>X据/span>-据/span>1据/span>=据/span>0.据/span>.据/span>
因式分解据span class="katex">
2据/span>X据/span>2据/span>+据/span>2据/span>X据/span>+据/span>2据/span>=据/span>0.据/span>.据/span>
因式分解据span class="katex">
2据/span>4.据/span>
X据/span>2据/span>+据/span>5.据/span>2据/span>
X据/span>+据/span>6.据/span>
=据/span>0.据/span>.据/span>