Forgot password?New user?Sign up
Existing user?Log in
2 x + 1 ( x + 1 ) ( x − 3 ) ( x + 4 ) = A ( x + 1 ) + B ( x − 3 ) + C ( x + 4 ) \ dfrac {2 x + 1} {(x+1)(x-3)(x+4)} = \dfrac{A}{(x+1)}\ + \dfrac{B}{(x-3)}\ + \dfrac{C}{(x+4)} (x+1)(x−3)(x+4)2x+1=(x+1)A+(x−3)B+(x+4)C
The above rational fraction is expressed in the form of partial fractions. Evaluate A + B + C A + B + C A+B+C.
Problem Loading...
Note Loading...
Set Loading...