Gauss' law to find capacitance Practice Problems Online

The concentric plates of a spherical capacitor have radii $a=4.1\text{ mm}$ and $b=4.6\text{ mm}.$ The above diagram shows the cross sectional feature of the capacitor. What is the approximate capacitance of the capacitor?

The value of the permittivity constant is $\varepsilon_0=8.85 \times 10^{-12} \text{ F/m}.$

2.1\text{ pF}

8.4\text{ pF}

4.2\text{ pF}

1.0\text{ pF}

铜sp的近似电容是什么here with a radius of $2.50\text{ mm}?$

The value of the permittivity constant is $\varepsilon_0=8.85 \times 10^{-12} \text{ F/m}.$

2.78 \times 10^{-13} \text{ F}

5.56 \times 10^{-12} \text{ F}

4.17 \times 10^{-13} \text{ F}

6.95 \times 10^{-12} \text{ F}

A cylindrical capacitor has radii $a=1.1\text{ mm}$ and $b=2.9\text{ mm}$ and length $L=6.0\text{ cm},$ as shown in the above cross sectional feature of the capacitor. What is the approximate capacitance of the capacitor?

The value of the permittivity constant is $\varepsilon_0=8.85 \times 10^{-12} \text{ F/m}.$

3.4\text{ pF}

17.2\text{ pF}

6.9\text{ pF}

12.0\text{ pF}

Suppose that $4$ identical mercury spheres with radius $R=1.20\text{ mm}$ are merged to one sphere. What is the approximate capacitance of the merged mercury drop?

The value of the permittivity constant is $\varepsilon_0=8.85 \times 10^{-12} \text{ F/m}.$

0.26 \text{ pF}

0.21 \text{ pF}

30.76 \text{ pF}

35.55 \text{ pF}

A parallel-plate capacitor has $58.0\text{ cm}^2$ of plate area and $1.20\text{ mm}$ separation. What is the approximate capacitance of the capacitor?

The value of the permittivity constant is $\varepsilon_0=8.85 \times 10^{-12} \text{ F/m}.$

0.4\text{ pF}

427.8\text{ pF}

4.3\text{ pF}

42.8\text{ pF}

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Gauss' law to find capacitance

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Gauss' law to find capacitance